110=-16t^2+96t+0.1

Solution for 110=-16t^2+96t+0.1 equation:

110=-16t^2+96t+0.1

We move all terms to the left:

110-(-16t^2+96t+0.1)=0

We get rid of parentheses

16t^2-96t-0.1+110=0

We add all the numbers together, and all the variables

16t^2-96t+109.9=0

a = 16; b = -96; c = +109.9;
Δ = b2-4ac
Δ = -962-4·16·109.9
Δ = 2182.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-\sqrt{2182.4}}{2*16}=\frac{96-\sqrt{2182.4}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+\sqrt{2182.4}}{2*16}=\frac{96+\sqrt{2182.4}}{32}
$